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I have a formula that I have been manually calculating for too long. Recently, I have gotten most of it to calculate in vba which is great, but I still need help with the last two steps. The first one is that:
I need in M18 of a worksheet for vba to calculate a standard deviation off of 90% of the records in column L. Now column L will always have a different base size from file to file, but the records always start in L28 and go down x records, where x can be as little as one and as great as 1000. Column L is already sorted, and I want the 90% to only exclude the high results (or rather, the formula will always include L28)
For example if there are 10 respondents in row L, than I want the formula in M18 to be
=STDEV(L28:L36)
The standard deviation in "descriptive statistics" in "data analysis" is sample standard deviation not population SD. How can I get the population SD?
Hi there, not sure if this is the right forum for this post, but anyway, here it goes.
I have a column of historical 5-year returns. For this data I need the standard deviation of the annualized results (that is, the 5-year returns raised to the power of 1/5). Is it possible to do this directly with the Stdev formula in Excel, or do I have to make a separate column for the annualized returns?
Regards
Hi Guys,
Just wanted to ensure ive got my methodology for calculating a standard deviation correct (workbook attached with forumula currently).
Then I will attach a file with it converted in VBA, but i may need a bit of help.
Just attempting to get to grips of the basis before i try to code it, would be intresting to see if we have any other macros for various calculations.
If my calculations are way off then any advice would be great
Hello, can anybody help me in this problem?
I would like to find the standard deviation of 10 cells in a column B9:B18. The sd should only include any number equal or larger than 0 in the range, but not any blank cells.
I did try the formula STDEV(B9:B18), but the outcome took blank cells as 0.
TQ.
In regards to Statistics, I was wondering if there is a standard deviation
function in Excel that will eliminate the long math.
Hi,
Would someone be able to help me with standard deviation within excel? I have used the formula =STDEV(number one, number two...etc). I think the problem is that my data is not a normal distribution, thus the incorrect standard deviation value. But I need to some how calculate standard deviation? Is there a way that I can with excel? I have over 20 000 data elements, thus making it harder to work out. Could someone please suggest some ideas that I could possibly implement to help correctly calculate standard deviation?
I want to take a data series and plot the mean and standard deviation on a
bar graph. How do I do this in excel?
Hello,
Can someone please help me with my query?
I have a large database and would like to calculate standard deviation based on a condition "Yes" or "No".
Shown below is a small layout from my database:
Criteria
Yes
Yes
No
No
Yes
Yes
No
No
Yes
Yes
No
No
Yes
Yes
No
No
Yes
Yes
No
No
Yes
Yes
No
No
Value
37.00
28.50
35.40
25.00
27.90
32.80
37.50
27.60
28.90
29.90
30.30
26.10
27.40
23.50
29.10
29.20
33.80
40.40
30.50
37.90
26.50
Manual Calculation Method:
Standard Deviation (All)
4.65
37.00
28.50
35.40
25.00
27.90
32.80
37.50
27.60
28.90
29.90
30.30
26.10
27.40
23.50
29.10
29.20
33.80
40.40
30.50
37.90
26.50
Standard Deviation (Yes)
2.96
37.00
28.50
27.90
32.80
28.90
29.90
26.10
27.40
29.10
29.20
30.50
Standard Deviation (No)
6.00
35.40
25.00
37.50
27.60
30.30
23.50
33.80
40.40
37.90
26.50
STDEV (No)
6.00
Conditional Calculation Method:
Standard Deviation (No)
6.31
The equation in cell B10 does not give the correct answer. The correct answer is in cell B7.
Note:
This is an example of my database. In the future, I will add more data columns, hence the formula looks upto column IV.
In cell B10, I am using the following array formula to calculate the standard deviation: "{=STDEV(($D$1:$IV$1="No")*(D2:IV2))}".
Please note that in some instances, the cell in the "Value" row will be blank. Again, I have shown this above.
Please can someone help me to obtain the correct answer of "6.00" and not "6.31" as calculated by the array formula.
What change(s) do I need to make to my array formula?
Many thanks.